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알고리즘/알고리즘 문제풀이

[HackerRank] Lonely Integer

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https://www.hackerrank.com/challenges/one-week-preparation-kit-lonely-integer

 

Lonely Integer | HackerRank

Find the unique element in an array of integer pairs.

www.hackerrank.com

#include <bits/stdc++.h>

using namespace std;

string ltrim(const string &);
string rtrim(const string &);
vector<string> split(const string &);

/*
 * Complete the 'lonelyinteger' function below.
 *
 * The function is expected to return an INTEGER.
 * The function accepts INTEGER_ARRAY a as parameter.
 */

int lonelyinteger(vector<int> a)
{
    // find a unique integer
    // 1. sort the array
    sort(a.begin(), a.end());
    // 2. check if the current element is equal to the next element
    // 3. if not, return the current element
    // 4. if yes, skip the next element and continue
    for (int i = 0; i < a.size(); i++)
    {
        if (a[i] == a[i + 1])
        {
            i++;
        }
        else
        {
            return a[i];
        }
    }
    return 0;
}

int main()
{
    ofstream fout(getenv("OUTPUT_PATH"));

    string n_temp;
    getline(cin, n_temp);

    int n = stoi(ltrim(rtrim(n_temp)));

    string a_temp_temp;
    getline(cin, a_temp_temp);

    vector<string> a_temp = split(rtrim(a_temp_temp));

    vector<int> a(n);

    for (int i = 0; i < n; i++) {
        int a_item = stoi(a_temp[i]);

        a[i] = a_item;
    }

    int result = lonelyinteger(a);

    fout << result << "\n";

    fout.close();

    return 0;
}

string ltrim(const string &str) {
    string s(str);

    s.erase(
        s.begin(),
        find_if(s.begin(), s.end(), not1(ptr_fun<int, int>(isspace)))
    );

    return s;
}

string rtrim(const string &str) {
    string s(str);

    s.erase(
        find_if(s.rbegin(), s.rend(), not1(ptr_fun<int, int>(isspace))).base(),
        s.end()
    );

    return s;
}

vector<string> split(const string &str) {
    vector<string> tokens;

    string::size_type start = 0;
    string::size_type end = 0;

    while ((end = str.find(" ", start)) != string::npos) {
        tokens.push_back(str.substr(start, end - start));

        start = end + 1;
    }

    tokens.push_back(str.substr(start));

    return tokens;
}

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